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3=-45w^2-24w
We move all terms to the left:
3-(-45w^2-24w)=0
We get rid of parentheses
45w^2+24w+3=0
a = 45; b = 24; c = +3;
Δ = b2-4ac
Δ = 242-4·45·3
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-6}{2*45}=\frac{-30}{90} =-1/3 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+6}{2*45}=\frac{-18}{90} =-1/5 $
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